| ⇦ | 
| ⇨ |
Small drops of the same size are charges to V volt each. If n such drops coalesce to form a single large drop, its potential will be
Options
(a) Vn
(b) V/n
(c) Vn¹/³
(d) Vn²/³
Correct Answer:
Vn²/³
Explanation:
Potential at the surface of a solid charged sphere = (1 /4πε₀).(q / a)
(4/3) πr³ × n = (4/3) πr’³
Due to n changes, Vn = (1 /4πε₀).(nq / r’),
r’ = rn¹/³
Vn = (1 /4πε₀).(nq / n¹/³ r) = V n²/³
Related Questions: - A particle executes simple harmonic oscillations with an amplitude
- Two solid discs of radii r and 2r roll from the top of an inclined plane
- A body of mass 3 kg acted upon by a constant force is displaced by S meter
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- The friction of the air causes a vertical retardation equal to 10%
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle executes simple harmonic oscillations with an amplitude
- Two solid discs of radii r and 2r roll from the top of an inclined plane
- A body of mass 3 kg acted upon by a constant force is displaced by S meter
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- The friction of the air causes a vertical retardation equal to 10%
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply