| ⇦ |
| ⇨ |
An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰ to an electric field of strength 10⁴ NC⁻¹. If it experiences a torque of Nm, the potential energy of the dipole is
Options
(a) 2.45 J
(b) 0.0245 J
(c) 245.0 J
(d) 24.5 J
Correct Answer:
24.5 J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Newton postulated his corpuscular theory on the basis of
- During an adiabatic process, the pressure of a gas is found to be proportional
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- In an AC generator, a coil with N turns, all of the same area A and total resistance R,
- A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Newton postulated his corpuscular theory on the basis of
- During an adiabatic process, the pressure of a gas is found to be proportional
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- In an AC generator, a coil with N turns, all of the same area A and total resistance R,
- A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Torque=PE sin¢
10√2= P×10^4 sin 30°
P=2√2×10^-3
U=PE cos 30°
U=2√2×10^-3× 10^4 cos 30°
=24.5 J
Torque=PE sin¢
10√2= P×10^4 sin 30°
P=2√2×10^-3
U=PE cos 30°
U=2√2×10^-3× 10^4 cos 30°
=24.5 J
Torque=PE sin¢
10√2= P×10^4 sin 30°
P=2√2×10^-3
U=PE cos 30°
U=2√2×10^-3× 10^4 cos 30°
=24.5 J