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Small drops of the same size are charges to V volt each. If n such drops coalesce to form a single large drop, its potential will be
Options
(a) Vn
(b) V/n
(c) Vn¹/³
(d) Vn²/³
Correct Answer:
Vn²/³
Explanation:
Potential at the surface of a solid charged sphere = (1 /4πε₀).(q / a)
(4/3) πr³ × n = (4/3) πr’³
Due to n changes, Vn = (1 /4πε₀).(nq / r’),
r’ = rn¹/³
Vn = (1 /4πε₀).(nq / n¹/³ r) = V n²/³
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