| ⇦ | 
| ⇨ |
The young’s modulus of steel is twice that of brass. Two wires of same length and of same area of cross section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weights addes to the steel and brass wires must be in the ratio of
Options
(a) -04:01:00
(b) -01:01:00
(c) -01:02:00
(d) -02:01:00
Correct Answer:
-02:01:00
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Charge Q is divided into two parts which are then kept some distance apart. The force
- The conducting loop in the form of a circle is placed in a uniform magneitc field
- As a result of interference of two coherent sources of light, energy is
- If the velocity of an electron increases, then its de Broglie wavelength will
- The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Charge Q is divided into two parts which are then kept some distance apart. The force
- The conducting loop in the form of a circle is placed in a uniform magneitc field
- As a result of interference of two coherent sources of light, energy is
- If the velocity of an electron increases, then its de Broglie wavelength will
- The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply