| ⇦ |
| ⇨ |
The electric field associated with an e.m. wave in vacuum is given by E = i 40 cos (kz – 6 x 10⁸ t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is:
Options
(a) 2 m⁻¹
(b) 0.5 m⁻¹
(c) 6 m⁻¹
(d) 3 m⁻¹
Correct Answer:
2 m⁻¹
Explanation:
On comparing the given equation to
E = a₀i cos (ωt – kz) ω = 6 x 10⁸ ,
k = 2π / r = ω / c
k = ω / c = 6 x 10⁸ / 3 x 10⁸ = 2 m⁻¹
Related Questions: - The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field
- A dust packet is dropped from 5th storey of a multi-storeyed building
- In the phenomenon of electric discharge through gases at low pressure,
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
- A thin wire of length L and mass M is bent to form a semicircle.
Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field
- A dust packet is dropped from 5th storey of a multi-storeyed building
- In the phenomenon of electric discharge through gases at low pressure,
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
- A thin wire of length L and mass M is bent to form a semicircle.
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply