| ⇦ | 
| ⇨ |
If R is the radius of the earth and g is the acceleration due to gravity on the earth surface, the mean density of the earth is
Options
(a) 4πG/3gR
(b) 3πG/4gR
(c) 3g/4πRG
(d)πRg/12G
Correct Answer:
3g/4πRG
Explanation:
Density = Mass/ Volume
= M / (4/3 π R³)
= (gR² / G). x 3/4 (1/π R³) [as g = GM/R²]
= (3/4π G) x (g/R)
=3g/4πRG
Related Questions: - A charged particle (charge q) is moving in a circle of radius R with uniform speed v
- When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles
- A body oscillates with amplitude of 10 cm in a horizontal platform.
- A particle moving in a straight line with uniform acceleration is observed
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A charged particle (charge q) is moving in a circle of radius R with uniform speed v
- When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles
- A body oscillates with amplitude of 10 cm in a horizontal platform.
- A particle moving in a straight line with uniform acceleration is observed
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply