| ⇦ | 
| ⇨ |
If R is the radius of the earth and g is the acceleration due to gravity on the earth surface, the mean density of the earth is
Options
(a) 4πG/3gR
(b) 3πG/4gR
(c) 3g/4πRG
(d)πRg/12G
Correct Answer:
3g/4πRG
Explanation:
Density = Mass/ Volume
= M / (4/3 π R³)
= (gR² / G). x 3/4 (1/π R³) [as g = GM/R²]
= (3/4π G) x (g/R)
=3g/4πRG
Related Questions: - If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- How much work is required to carry a 6 μC charge from the negative terminal
- The magnetic field at a point on the axis of a long solenoid having 5 turns per cm
- The flux linked with a circuit is given by φ=t³+3t-7. The graph between time
- The dimensions of magnetic field intensity B are
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- How much work is required to carry a 6 μC charge from the negative terminal
- The magnetic field at a point on the axis of a long solenoid having 5 turns per cm
- The flux linked with a circuit is given by φ=t³+3t-7. The graph between time
- The dimensions of magnetic field intensity B are
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply