| ⇦ | 
| ⇨ |
If R is the radius of the earth and g is the acceleration due to gravity on the earth surface, the mean density of the earth is
Options
(a) 4πG/3gR
(b) 3πG/4gR
(c) 3g/4πRG
(d)πRg/12G
Correct Answer:
3g/4πRG
Explanation:
Density = Mass/ Volume
= M / (4/3 π R³)
= (gR² / G). x 3/4 (1/π R³) [as g = GM/R²]
= (3/4π G) x (g/R)
=3g/4πRG
Related Questions: - The ratio of amplitude of magnetic field to the amplitude of electric field for
- “On flowing current in a conducting wire the magnetic field is produced around it”.
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- You are marooned on a frictionless horizontal plane and cannot exert any horizontal
- Potential at a point x-distance from the centre inside the conducting sphere
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- “On flowing current in a conducting wire the magnetic field is produced around it”.
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- You are marooned on a frictionless horizontal plane and cannot exert any horizontal
- Potential at a point x-distance from the centre inside the conducting sphere
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply