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A particle of masses m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is
Options
(a) √( 2GM / R)
(b) √( 2GM / R)²
(c) √( 2G R²)
(d) √( 2GM / R)²
Correct Answer:
√( 2GM / R)
Explanation:
The velocity u should be equal to the escape velocity. That is, u = √(2gR)
But g = GM / R² ⇒ u = √(2 . GM / R² . R)
√( 2GM / R)
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
- Acceleration of a particle, executing SHM, at its mean position is
- A simple pendulum oscillates in a vertical plane. When it passes through the mean
- When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy
- The most stable particle in Baryon group is
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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