| ⇦ | 
| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
- A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- The nuclei of which one of the following pairs of nuclei are isotones?
- An open knife edge of mass 200g is dropped from height 5m on a cardboard
- A parallel beam of light of wavelength λ is incident normally on a narrow slit
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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