| ⇦ | 
| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - An unpolarised beam of intensity I is incident on a pair of nicols making an angle
- A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV.
- The electric vector vibration of an electromagnetic wave is given by
- An ideal gas is expanding such that PT²=constant. The coefficient of volume
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An unpolarised beam of intensity I is incident on a pair of nicols making an angle
- A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV.
- The electric vector vibration of an electromagnetic wave is given by
- An ideal gas is expanding such that PT²=constant. The coefficient of volume
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply