| ⇦ | 
| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
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- A common emitter amplifier has a voltage gain of 50, an input impedance of 100Ω
- An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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