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A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- Two Carnot engine A and B are operated in series. The engine A receives
- The charges Q, +q, and +q are placed at the vartices of an equilateral
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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