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A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a given velocity, a projectile has the same range R for two angles of projection.
- A magnet of length 10 cm and magnetic moment 1 A-m² is placed
- A 5 watt source emits monochromatic light of wavelength 5000Å. When placed
- What is the value of Ā+A in the Boolean algebra?
- The maximum number of possible interference maxima for slit-seperation equal to
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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