What is the energy of photon whose wavelength is 6840 Å?

What Is The Energy Of Photon Whose Wavelength Is 6840 Physics Question

What is the energy of photon whose wavelength is 6840 Å?

Options

(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)

Correct Answer:

(1.81 eV)

Explanation:

λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å

Related Questions:

  1. Two particles A and B, move with constant velocities V₁ and V₂. At the initial
  2. Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric
  3. A solid which is transparent to visible light and whose conductivity increases
  4. The given graph represents V-I characteristic for a semiconductor device
  5. Electrons used in an electron microscope are accelerated by a voltage of 25 kV

Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*