| ⇦ | 
| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - A body travelling along a straight line traversed one-third of the total distance
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- A cell of emf E and internal resistance r supplies current for the same time
- Angle of contact of a liquid with a solid depends on
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body travelling along a straight line traversed one-third of the total distance
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- A cell of emf E and internal resistance r supplies current for the same time
- Angle of contact of a liquid with a solid depends on
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply