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What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - The sum of the magnitudes of two forces acting at a point is 16 N
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The sum of the magnitudes of two forces acting at a point is 16 N
- A radioactive substance contains 10000 nuclei and its halflife period is 20 days
- If λ₁ and λ₂ are the wavelengths of the first members of the Lyman and Paschen
- Laser beams are used to measure long distance because
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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