| ⇦ | 
| ⇨ |
What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A calorimeter contains 0.2 kg of water at 30° C. 0.1kg of water at
- Force required to move a mass of 1kg at rest on a horizontal rough plane
- The potential difference that must be applied to stop the fastest photoelectrons
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- In the Young’s double slit experiment, a point P on the central bright fringe
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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