| ⇦ | 
| ⇨ |
A small part of the rim of a fly wheel breaks off while it is rotating at a constant angular speed. Then its radius of gyration will
Options
(a) Increase
(b) Decrease
(c) Remain unchanged
(d) Nothing definite can be said
Correct Answer:
Decrease
Explanation:
Iω is conserved. If a small piece is broken. I will be less and ω will increase But I = mk², as I is less, m is small, k² also will be small. The radius of gyration also will decrease.
Related Questions: - The amount of heat energy required to raise the temperature of 1 g of Helium
- In photoelectric emission process from a metal of work function
- In a transistor, the value of βis 100, then the value of α will be
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- In adiabatic expansion, product of PV
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The amount of heat energy required to raise the temperature of 1 g of Helium
- In photoelectric emission process from a metal of work function
- In a transistor, the value of βis 100, then the value of α will be
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- In adiabatic expansion, product of PV
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Due to decrease in the mass of the flywheel M.I. decreases. To conserve angular momentum angular velocity of flywheel increases.