| ⇦ | 
| ⇨ |
Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
Related Questions: - The power obtained in a reactor using U²³⁵ disintegration is 1000 kW
- The excess pressure inside one soap bubble is three times that inside a second soap bubble
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- A radioactive substance decays to 1/16th of its initial activity in 40 days.
- A p-n photodiode is made of a material with a band gap of 2.0 eV
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The power obtained in a reactor using U²³⁵ disintegration is 1000 kW
- The excess pressure inside one soap bubble is three times that inside a second soap bubble
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- A radioactive substance decays to 1/16th of its initial activity in 40 days.
- A p-n photodiode is made of a material with a band gap of 2.0 eV
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply