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A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
Related Questions: - Which of the following is true for number of spectral lines in going from Lyman series
- A body is under stress F and has Young’s modulus Y, then the energy
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is true for number of spectral lines in going from Lyman series
- A body is under stress F and has Young’s modulus Y, then the energy
- A particle in simple harmonic motion is described by the displacement function
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- If voltage across a bulb rated 220 volt-100 Watt drops by 2.5% of its rated value
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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