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A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A perfect gas at 27° C is heated at constant pressure to 327° C. If original volume of gas
- Kirchoff’s I law and II laws of electricity prove respectively the
- A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils.
- A source of sound of frequency 256 Hz is moving rapidly towards a wall with a velocity
- Heat is flowing through a rod of length 50 cm and area of cross-section 5 cm².
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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