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A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
Related Questions: - According to photon theory of light which of the following physical quantities,
- In atom bomb, the reaction which occurs is
- 1 a.m.u. is equivalent to
- The excitation potential of hydrogen atom in the first excited state is
- 10 mA current can pass through a galvanometer of resistance 25 ohm.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- According to photon theory of light which of the following physical quantities,
- In atom bomb, the reaction which occurs is
- 1 a.m.u. is equivalent to
- The excitation potential of hydrogen atom in the first excited state is
- 10 mA current can pass through a galvanometer of resistance 25 ohm.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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