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A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
- The input signal given to a CE amplifier having a voltage gain of 150 is
- The equation of state for 5 g of oxygen at a pressure P and temperature T,
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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