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At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110⁰ C this ratio is:
Options
(a) x
(b) (383 / 283) x
(c) (10 / 110) x
(d) (283 / 383) x
Correct Answer:
(283 / 383) x
Explanation:
Let the mass of the gas be m. AT fixed temperature and pressure, volume is fixed. Density of the gas, ρ = m / V
Now ρ / P = m / PV = M / nRT = x (By question)
xT = constant x₁T₁ = x₂T₂
x₂ = x₁T₁ / T₂ = (283 / 383) x
[T₁ = 283 K, T₂ = 383 K ]
Related Questions: - Match the following columns about collision
- The amount of heat energy required to raise the temperature of 1 g of Helium
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Match the following columns about collision
- The amount of heat energy required to raise the temperature of 1 g of Helium
- A monoatomic gas is suddenly compressed to (1/8)th of its initial volume adiabatically.
- A gas is suddenly expanded such that its final volume becomes 3 times
- When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Very good one..
I saw same answer on other site as well but they were too lengthy.