A simple pendulum performs simple harmonic motion about x = 0 with an amplitude

A Simple Pendulum Performs Simple Harmonic Motion About X Physics Question

A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:

Options

(a) πa / T
(b) 3π²a / T
(c) πa√3 / T
(d) πa√3 / 2T

Correct Answer:

πa√3 / T

Explanation:

Speed v = ? √(a² – x²) , x = a / 2
v = ? √(a² – a² / 4) = ? √(3a² / 4) = 2π / T . a√3 / 2
πa√3 / T

Related Questions:

  1. The transverse nature of electromagnetic waves is proved by which of the following?
  2. When a ceiling fan is switched off its angular velocity reduces to 50% while
  3. In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
  4. The unit of surface tension is
  5. A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude

Topics: Oscillations (58)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*