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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
Related Questions: - A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- Two closed organ pipes when sounded simultaneously give 4 beats/second.
- A susceptibility of a certain magnetic material is 400. What is the class
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
- A glass flask weighing 390 g having internal volume 500 cc just floats
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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