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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
Related Questions: - If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- A neutron is moving with a velocity u.It collides head on and elastically with an atom
- The magnetic susceptibility does not depend upon the temperature in
- The half-life of radioactive element is 600 yr. The fraction of sample
- If R is the radius of the earth and g is the acceleration due to gravity
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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