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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- Light of wavelength λ is incident on slit of width d. The resulting diffraction
- Which of the following atoms has the lowest ionisation potential?
- A wheel is rotating at 900 rpm about its axis.When the power is cut-off it
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Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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