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The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Options
(a) The speed of light in vacuum
(b) reciprocal of speed of light in vacuum
(c) the ratio of magnetic permeability to the electric susceptibility of vacuum
(d) unity
Correct Answer:
reciprocal of speed of light in vacuum
Explanation:
The average energy stored in the electric field Uᴇ = (1/2) ε₀E²
The average energy stroed in the magnetic field Uв = (1/2) . (B² /μ₀),
According to conservation of energy Ue = Ub
ε₀μ₀ = B² / E²
B / E = √(ε₀μ₀) = 1/C
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- The Rutherford scattering experiment proves that an atom consists of
- A machine gun fires 10 bullets/s,each of mass 10 g,the speed of each bullet
- If capillary experiment is performed in vaccum, then a liquid under the condition
- A thermocouple is made from two metals, antimony and bismuth. If one junction
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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