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An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity ε = 4.0. Then
Options
(a) wavelength is doubled and frequency is unchanged
(b) wavelength is doubled and frequency becomes half
(c) wavelength is halved and frequency remains unchanged
(d) wavelength and frequency both remain unchanged
Correct Answer:
wavelength is halved and frequency remains unchanged
Explanation:
Given : frequency f = 2 MHz, relative permitivity εᵣ = 4
For formula,
velocity v = c / √εᵣ = c / 2
λ’ = λ / 2
[since frequency remains unchanged ]
Related Questions: - When radiation is incident on a photoelectron emitter,
- Potentiometer measures the potential difference more accurately than a voltmeter
- An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When radiation is incident on a photoelectron emitter,
- Potentiometer measures the potential difference more accurately than a voltmeter
- An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- A series L-C-R circuit contains inductance 5 mH, capacitance 2 μF and resistance
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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