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A particle moving in a straight line with uniform acceleration is observed to be a distance a from a fixed point initially.It is at distance b,c,d from the same point after n,2n,3n seconds.The acceleration of the particle is
Options
(a) (c-2b+a)/n²
(b) (c+b+a)/9n²
(c) (c+2b+a)/4n²
(d) (c-b+a)/n²
Correct Answer:
(c-2b+a)/n²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron in hydrogen atom makes a transition n₁ → n₂
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
- In Moseley’s law √ν=a(z-b), the values of the screening constant for K-series
- The vector sum of two forces is perpendicular to their vector difference. In that case,
- A stone of mass 1 kg tied to a light inexensible string of length L=10/3 is whirling
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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