Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary

⇦

⇨

Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:

Options

(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero

Correct Answer:

Mv newton

Explanation:

F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.

Related Questions:

1. A parallel plate air capacitor has capacity C, distance of seperation between plate
2. When one of the slits of Young’s experiment is covered with a transport sheet
3. The depletion layer in the p-n junction region is caused by
4. Suppose the kinetic energy of a body oscillating with amplitude A and at a distance
5. Watt hour mter measures

Topics: Laws of Motion (103)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends