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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A boat of mass 40 kg is at rest.A dog of mass 4 kg moves in the boat
- An avarage induced e.m.f. of 1 V appears in a coil when the current in it is changed
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- The value of workdone for rotating a magnet of magnetic moment M by an angle θ in external
- An electron in hydrogen atom makes a transition n₁ → n₂
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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