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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- Light from the constellation Virgo is observed to increase in wavelength by 0.4%
- A person cannot see the objects clearly placed at a distance more than 40 cm
- An electric motor operating on a 60 volt D.C supply draws a current of 10 amp.
- A car accelerates from rest at constant rate for first 10s and covers a distance x.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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