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A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is 45°, the speed of the car is :
Options
(a) 20 ms⁻¹
(b) 30 ms⁻¹
(c) 5ms⁻¹
(d) 10 ms⁻¹
Correct Answer:
30 ms⁻¹
Explanation:
For banking tan θ = V² / Rg
tan 45 = V² / 90 x 10 = 1
V = 30 m/s
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The logic behind NOR gate is that it gives
- The electron of a hydrogen atom revolves round the proton in a circular
- The wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
- The phase difference between the flux linked with a coil rotating in a uniform
- The valence band and the conductance band of a solid overlap at low temperature
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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