| ⇦ |
| ⇨ |
The value of workdone for rotating a magnet of magnetic moment M by an angle θ in external magnetic field H is given by
Options
(a) MH cos θ
(b) 2MH sin²(θ/2)
(c) MH sin θ
(d) MH (1-sin²θ)
Correct Answer:
MH cos θ
Explanation:
MH (1 – cos θ) = work done
.·. W = MH [1 – 1 + 2 sin² (θ / 2)] = 2MH sin² (θ / 2)
Related Questions: - A calorimeter contains 0.2 kg of water at 30° C. 0.1kg of water at
- A particle of mass m is projected with a velocity v making an angle of 45°
- What is the energy of He⁺ electron in first orbit?
- A battery having e.m.f. 4 volt and internal resistance 0.5 Ω is connected
- Two straight wires each 10cm long are parallel to one another and seperated by 2 cm.
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A calorimeter contains 0.2 kg of water at 30° C. 0.1kg of water at
- A particle of mass m is projected with a velocity v making an angle of 45°
- What is the energy of He⁺ electron in first orbit?
- A battery having e.m.f. 4 volt and internal resistance 0.5 Ω is connected
- Two straight wires each 10cm long are parallel to one another and seperated by 2 cm.
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

B is the right option