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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transformer is used to light a 100 W and 110 V lamp from a 220 V mains.
- A electric dipole is placed at an angle of 30⁰ to a non-uniform electric field.
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
- The dimensions of Planck’s constant is same as that of
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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