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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An open pipe resonates with a tuning fork of frequency 500 Hz. It is observed
- When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V
- In a common emitter (CE) amplifier having a voltage gain G, the transistor
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- A spring has time period T. It is cut into n equal parts. The time period of each part
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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