| ⇦ | 
| ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - In Raman effect, Stoke’s lines are spectral lines having
- The relationship between decay constant λ and half-life T of a radioactive substance is
- A short linear object of length L lies on the axis of a spherical mirror of focal
- A heavy uniform chain lies on a horizontal top table.If the coefficient of friction
- If fundamental frequency of closed pipe is 50 Hz then frequency of 2nd overtone
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Raman effect, Stoke’s lines are spectral lines having
- The relationship between decay constant λ and half-life T of a radioactive substance is
- A short linear object of length L lies on the axis of a spherical mirror of focal
- A heavy uniform chain lies on a horizontal top table.If the coefficient of friction
- If fundamental frequency of closed pipe is 50 Hz then frequency of 2nd overtone
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply