| ⇦ | 
| ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - Two lines of force due to a bar magnet
- The mirrors are inclined at an angle of 50⁰. The number of images formed for an object
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- The escape velocity from the earth is Ve. The escape velocity from a planet
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two lines of force due to a bar magnet
- The mirrors are inclined at an angle of 50⁰. The number of images formed for an object
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- The escape velocity from the earth is Ve. The escape velocity from a planet
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply