| ⇦ |
| ⇨ |
In an L-C-R series resonant circuit, the capacitance is changed from C to 4C. For the same resonant frequency, the inductance should be changed from L to
Options
(a) 2L
(b) L/2
(c) 4L
(d) L/4
Correct Answer:
L/4
Explanation:
We know that, In L-C-R circuit, f = (1 / 2π) √(1 / LC) For the same resonant frequency, the inductance should be changed from L to (L / 4).
Related Questions: - A rod of weight W is supported by two parallel knife edges A and B is in equilibrium
- The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle
- Consider a uniform square plate of side ɑ and mass m. The moment of inertia
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A rod of weight W is supported by two parallel knife edges A and B is in equilibrium
- The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle
- Consider a uniform square plate of side ɑ and mass m. The moment of inertia
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply