| ⇦ |
| ⇨ |
A rod of weight W is supported by two parallel knife edges A and B is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is
Options
(a) Wd/x
(b) W(d-x)/x
(c) W(d-x)/d
(d) Wx/d
Correct Answer:
W(d-x)/d
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The temperature of ideal gas is reduced from 927° C to 27° C. The r.m.s velocity
- A point charge q is situated at a distance r on axis from one end of a thin
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- The time period of a thin bar magnet in Earth’s magnetic field is T
- A charge Q is enclosed by a Gaussian spherical surface of radius R
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The temperature of ideal gas is reduced from 927° C to 27° C. The r.m.s velocity
- A point charge q is situated at a distance r on axis from one end of a thin
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- The time period of a thin bar magnet in Earth’s magnetic field is T
- A charge Q is enclosed by a Gaussian spherical surface of radius R
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply