The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity

The Acceleration Due To Gravity Becomes G2 Where Gacceleration Due Physics Question

The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity on the surface of the earth at a height equal to

Options

(a) 4R
(b) R/4
(c) 2R
(d) R/2

Correct Answer:

R/4

Explanation:

Acceleration due to gravity g=GM/R² Acceleration due to gravity on the surface of the height is g’ = GM/(R+h)² .·. g/g’ = (GM/R²)/(GM/(R+h)²) = (R+h/R)² = (1+h/R)² g’/g = (1+h/R)⁻² = (1-2h/R), When h<<R (g/2)/g = (1-2h/R) ⇒ 1/2 = (1-2h/R) ⇒ 2h/R = 11/2 ⇒ 2h/R = 1/2 ⇒ h = (1/2)(R/2) = R/4

Related Questions:

  1. The maximum wavelength of radiations emitted at 900K is 4 µm. What will be the maximum
  2. In Young’s double silt experiment if the distance between the two slits
  3. A cyclotron is used to accelerate
  4. A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
  5. A spring when stretched by 2mm containing energy 4 J. If it is stretched

Topics: Gravitation (63)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

1 Comment on The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity

Leave a Reply

Your email address will not be published.


*