| ⇦ |
| ⇨ |
The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle will be
Options
(a) 9.6 x 10⁷ C kg⁻¹
(b) 19.2 x 10⁷ C kg⁻¹
(c) 4.8 x 10⁷ C kg⁻¹
(d) 2.4 x 10⁷ C kg⁻¹
Correct Answer:
4.8 x 10⁷ C kg⁻¹
Explanation:
For proton, specific charge = e / m = 9.6 × 10⁷ C kg⁻¹
For alpha particle, specific charge = 2e / 4m = 1e / 2m
= (1/2) × 9.6 × 10⁷ = 4.8 × 10⁷ C kg⁻¹
Related Questions: - A metal bar of length L and area of cross-section A is clamped between two rigid
- Ring, hollow ring and solid sphere are rolled down from inclined plane
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
- In a circuit, 5% of total current passes through a galvanometer. If resistance
- A particle is under two mutually perpendicular simple harmonic motions
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A metal bar of length L and area of cross-section A is clamped between two rigid
- Ring, hollow ring and solid sphere are rolled down from inclined plane
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
- In a circuit, 5% of total current passes through a galvanometer. If resistance
- A particle is under two mutually perpendicular simple harmonic motions
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply