| ⇦ | 
| ⇨ |
In a circuit, L,C and R are connected in series with an alternating voltage source of frequency f. The current leads the voltage by 45⁰. The value of C is
Options
(a) 1/πf(2πfL+R)
(b) 1/πf(2πfL-R)
(c) 1/2πf(2πfL-R)
(d) 1/2πf(2πfL+R)
Correct Answer:
1/2πf(2πfL+R)
Explanation:
The phase difference ɸ between current and voltage is given by
tan ɸ = (Xʟ – Xc) / R
(Xʟ – Xc) / R = tan 45° = 1 ⇒ Xc = X⇒ + R
1 / 2πfC = 2πfL + R
Therefore, C = 1 / 2πf(2πfL + R)
Related Questions: - Moderator used in nuclear reactor is
- Energy of photon whose frequency is 10¹² MHz will be
- If force is proportional to square of velocity, then the dimension of proportionality
- If light emitted from sodium bulb is passed through sodium vapour,
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Moderator used in nuclear reactor is
- Energy of photon whose frequency is 10¹² MHz will be
- If force is proportional to square of velocity, then the dimension of proportionality
- If light emitted from sodium bulb is passed through sodium vapour,
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply