| ⇦ | 
| ⇨ |
In a circuit, L,C and R are connected in series with an alternating voltage source of frequency f. The current leads the voltage by 45⁰. The value of C is
Options
(a) 1/πf(2πfL+R)
(b) 1/πf(2πfL-R)
(c) 1/2πf(2πfL-R)
(d) 1/2πf(2πfL+R)
Correct Answer:
1/2πf(2πfL+R)
Explanation:
The phase difference ɸ between current and voltage is given by
tan ɸ = (Xʟ – Xc) / R
(Xʟ – Xc) / R = tan 45° = 1 ⇒ Xc = X⇒ + R
1 / 2πfC = 2πfL + R
Therefore, C = 1 / 2πf(2πfL + R)
Related Questions: - The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- At the first minimum adjacent to the central maximum of a single-slit diffraction
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- At the first minimum adjacent to the central maximum of a single-slit diffraction
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply