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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a mass spectrometer used for measuring the masses of ions, the ions
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- The maximum and minimum magnitudes of the resultant of two vectors
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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