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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circular disc of radius R and thickness R/6 has moment of inertia I about an axis
- A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state
- A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- A body of mass m is accelerated uniformly from rest to a speed v in a time T
- Aperture of human eye is 0.2 cm. The minimum magnifying power of a visual
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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