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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- A block of mass m is placed on a smooth wedge of inclination θ
- Under the action of a force F=cx, the position of a body changes from 0 to x.The work done
- A body of mass m is orbiting the earth at a radius r from the center of earth
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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