| ⇦ | 
| ⇨ |
In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected to a capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is
Options
(a) 10 mA
(b) 100 mA
(c) 200 mA
(d) 20 mA
Correct Answer:
20 mA
Explanation:
Vᵣₘₛ = 200 √2 / √2 = 200 V
Iᵣₘₛ = Vᵣₘₛ / Xc = 200/1 / 100 x 10⁻⁶
= 2 x 10⁻² = 20 mA
Related Questions: - The amount of heat energy required to raise the temperature of 1 g of Helium
- In a uniform circular motion,
- An electric motor runs on DC source of emf 200 V and draws a current of 10 A.
- The dimensions of latent heat are
- Acceleration of a particle, executing SHM, at its mean position is
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The amount of heat energy required to raise the temperature of 1 g of Helium
- In a uniform circular motion,
- An electric motor runs on DC source of emf 200 V and draws a current of 10 A.
- The dimensions of latent heat are
- Acceleration of a particle, executing SHM, at its mean position is
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
10^-6 is wrong it will be 10*10^-6=10^-5 so correct answer 200mA
V(rms) = 200 √2 / √2 = 200 V
I(rms) = V(rms) / Xc = (200/1) / (100 x 10⁻⁶)
= 2 x 10⁻² = 20 mA