| ⇦ |
| ⇨ |
For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be
Options
(a) straight line
(b) circle
(c) parabola
(d) ellipse
Correct Answer:
parabola
Explanation:
Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.
Related Questions: - 4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas
- A cyclotron is used to accelerate
- The de-Broglie wavelength of neutron in thermal equilibrium at temperature T is
- Einstein’s photoelectric equation is
- Moment of inertia, along the diameter of a ring is
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas
- A cyclotron is used to accelerate
- The de-Broglie wavelength of neutron in thermal equilibrium at temperature T is
- Einstein’s photoelectric equation is
- Moment of inertia, along the diameter of a ring is
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply