| ⇦ |
| ⇨ |
The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is
Options
(a) π
(b) 0.707π
(c) zero
(d) 0.5π
Correct Answer:
0.5π
Explanation:
Let y = A sin ωt
vinst = dy/ dt = Aω cos ωt
vinst = Aω² sin (ωt + π/2)
Acceleration = – Aω² sin ωt = Aω²sin (π + ωt)
ɸ = π/2 = 0.5 π.
Related Questions: - The two ends of a rod of length L and a uniform cross-sectional area
- A long solenoid has 500 turns. When a current of 2 ampere is passed through it
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
- Weight of a body of mass m decreases by 1% when it is raised to height h
- Light is emitted when
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The two ends of a rod of length L and a uniform cross-sectional area
- A long solenoid has 500 turns. When a current of 2 ampere is passed through it
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
- Weight of a body of mass m decreases by 1% when it is raised to height h
- Light is emitted when
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply