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For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be
Options
(a) straight line
(b) circle
(c) parabola
(d) ellipse
Correct Answer:
parabola
Explanation:
Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.
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Topics: Oscillations
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass m moves with constant speed along a circular path of radius r under
- A block of mass M is attached to the lower end of a vertical spring
- The magnetic field due to a current carrying circular loop of radius 3 cm at a point
- A shell of mass 200 g is ejected from a gun of mass 4 kg by an explosion
- In a LCR series circuit, the potential difference between the terminals of the inductor
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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