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For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be
Options
(a) straight line
(b) circle
(c) parabola
(d) ellipse
Correct Answer:
parabola
Explanation:
Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
- A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- Tangent galvanometer is used to measure
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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