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For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be
Options
(a) straight line
(b) circle
(c) parabola
(d) ellipse
Correct Answer:
parabola
Explanation:
Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- A particle moves with constant speed v along a circular path of radius r and completes
- Electromagnetic induction is not used in
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- An electric current passes through a long straight wire
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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