| ⇦ |
| ⇨ |
The total energy of a simple harmonic oscillator is proportional to
Options
(a) square root of displacement
(b) velocity
(c) frequency
(d) square of amplitude
Correct Answer:
square of amplitude
Explanation:
The total energy of a simple harmonic oscillator
(1/2). mω²A² (or) (1/2). kA²
Therefore it is proportional to the square of the amplitude.
Related Questions: - Copper of fixed volume V is drawn into wire of length l. When this wire is subjected
- Charge passing through a conductor of cross-section area A=0.3 m² is given
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- Let A = i Acosθ +j B sinθ be any vector.Another vector B which is normal to A is
- A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Copper of fixed volume V is drawn into wire of length l. When this wire is subjected
- Charge passing through a conductor of cross-section area A=0.3 m² is given
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- Let A = i Acosθ +j B sinθ be any vector.Another vector B which is normal to A is
- A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply