| ⇦ | 
| ⇨ |
A particle is executing the motion x=Acos (ωt-θ). The maximum velocity of the particle is
Options
(a) Aω cosθ
(b) Aω
(c) Aω sinθ
(d) None of these
Correct Answer:
Aω
Explanation:
x = A cos (ωt – θ)
Velocity = dx/dt = -A sin (ωt – θ)
For maximum value, Since function should be = 1
Maximum velocity = -Aω
Related Questions: - The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- A heavy stone hanging from a massless string of length 15 m is projected
- An electron of a stationary hydrogen atom passes from the fifth energy level to
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- A heavy stone hanging from a massless string of length 15 m is projected
- An electron of a stationary hydrogen atom passes from the fifth energy level to
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply