| ⇦ |
| ⇨ |
The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:
Options
(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹
Correct Answer:
ML⁻¹T⁻²
Explanation:
1/2 ?¬ツタE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?¬ツタE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²
Related Questions: - A disc of mass 100 g is kept floating horizontally in air by firing bullets
- At absolute temperature, the kinetic energy of the molecules
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- A concave mirror of focal length f₁ is placed at a distance d from a convex lens
- On adjusting the P-N junction diode in forward bias,
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A disc of mass 100 g is kept floating horizontally in air by firing bullets
- At absolute temperature, the kinetic energy of the molecules
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- A concave mirror of focal length f₁ is placed at a distance d from a convex lens
- On adjusting the P-N junction diode in forward bias,
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply