| ⇦ |
| ⇨ |
The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:
Options
(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹
Correct Answer:
ML⁻¹T⁻²
Explanation:
1/2 ?¬ツタE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?¬ツタE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²
Related Questions: - A particle is moving with a uniform velocity along a straight line path
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- A fluid is in streamline flow across a horizontal pipe of variable area of cross section
- An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is moving with a uniform velocity along a straight line path
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- A fluid is in streamline flow across a horizontal pipe of variable area of cross section
- An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply