A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is

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A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is

Options

(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these

Correct Answer:

50 Hz

Explanation:

Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz

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Topics: Waves (80)
Subject: Physics (2479)

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