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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- A block of mass m is placed on a smooth wedge of inclination θ
- A parallel plate condenser has a uniform electric field E(V/m) in the space between
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- Heat is not being exchanged in a body. If its internal energy is increased, then
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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