| ⇦ | 
| ⇨ |
If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
Related Questions: - The damping force on an oscillator is directly proportional to the velocity.
- If temperature of gas increases from 27°C to 927°C, the kinetic energy will be
- An aeroplane flies 400m due to North and then 300m due to south and then flies
- Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å
- A 2 kg mass starts from rest on an inclined smooth surface with inclination
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The damping force on an oscillator is directly proportional to the velocity.
- If temperature of gas increases from 27°C to 927°C, the kinetic energy will be
- An aeroplane flies 400m due to North and then 300m due to south and then flies
- Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å
- A 2 kg mass starts from rest on an inclined smooth surface with inclination
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply