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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- The de-Broglie wavelength of a proton(charge = 1.6 x 10⁻¹⁹ C, Mass = 1.6 x 10⁻²⁷ kg)
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum
- A ballon rises from rest with a constant acceleration g/8. A stone is released
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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