| ⇦ | 
| ⇨ |
If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
Related Questions: - A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- A block of mass m is placed on a smooth wedge of inclination θ
- A parallel plate condenser has a uniform electric field E(V/m) in the space between
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- Heat is not being exchanged in a body. If its internal energy is increased, then
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- A block of mass m is placed on a smooth wedge of inclination θ
- A parallel plate condenser has a uniform electric field E(V/m) in the space between
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- Heat is not being exchanged in a body. If its internal energy is increased, then
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply