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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The distance of the closest approach of an alpha particle fired at a nucleus
- When one of the slits of Young’s experiment is covered with a transport sheet
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
- If particles are moving with same velocity, then maximum de Broglie wavelength will
- A short circuited coil is placed in a magnetic field varying with time. Electrical
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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