A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is

A Tuning Fork Vibrates With 2 Beats In 004 Second Physics Question

A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is

Options

(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these

Correct Answer:

50 Hz

Explanation:

Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz

Related Questions:

  1. The potential energy of a simple harmonic oscillator when the particle is half way
  2. A parallel plate condenser has a uniform electric field E(V/m) in the space between
  3. In Young’s double slit experiment with sodium vapour lamp of wavelength
  4. A steady current is passing through a linear conductor of non-uniform cross-section.
  5. When a piece of metal is illuminated by a monochromatic light of wavelength λ,

Topics: Waves (80)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*