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A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is
Options
(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these
Correct Answer:
50 Hz
Explanation:
Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Initial angular velocity of a circular disc of mass M is ?￢ﾂﾁ.Then, two small spheres
- A wire carrying current I has the shape as shown in adjoining figure. Linear parts
- A ball of mass 2 kg and another of mass 4 kg are dropped together from
- A particle falls towards earth from infinity. Its velocity on reaching the earth
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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