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A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is
Options
(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these
Correct Answer:
50 Hz
Explanation:
Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bar magnet of moment M and pole strength m is cut into parts of equal lengths.
- The self-inductance of a coil having 500 turns is 50mH. The magnetic flux
- The velocity v of waves produced in water depends on their wavelength λ, the density
- The number of NAND gates required to form an AND gate is
- A wire in the form of a circular loop of one turn, carrying a current, produces
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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