| ⇦ |
| ⇨ |
A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is
Options
(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these
Correct Answer:
50 Hz
Explanation:
Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz
Related Questions: - A bar magnet of moment M and pole strength m is cut into parts of equal lengths.
- The self-inductance of a coil having 500 turns is 50mH. The magnetic flux
- The velocity v of waves produced in water depends on their wavelength λ, the density
- The number of NAND gates required to form an AND gate is
- A wire in the form of a circular loop of one turn, carrying a current, produces
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bar magnet of moment M and pole strength m is cut into parts of equal lengths.
- The self-inductance of a coil having 500 turns is 50mH. The magnetic flux
- The velocity v of waves produced in water depends on their wavelength λ, the density
- The number of NAND gates required to form an AND gate is
- A wire in the form of a circular loop of one turn, carrying a current, produces
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply