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A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is
Options
(a) (v1v2)/(v1+v2)
(b) (2v1v2)/(v1+v2)
(c) (2v1²v2²)/(v1²+v2²)
(d) (v1+v2)/2
Correct Answer:
(2v1v2)/(v1+v2)
Explanation:
Let the tot. distance covered by the particles be 2s. Then
vₐᵥ = 2 s / (s/ v₁ + s/ v₂) = 2 v₁v₂ / v₁ + v₂
Related Questions: - A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
- Three fourth of the active material decays in a radioactive sample in 3/4 sec
- A beam of light of wavelength 600 nm from a distant source falls
- The emission line of Lyman corresponds to the absorption line in laboratory temperature
- Three unequal resistors in parallel are equivalent to a resistance 1 Ω.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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