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A particle of mass m is driven by a machine that delivers a constant power k watts.If the particle starts from rest the force on the particle at time t is
Options
(a) √(mk/2) t⁻¹/²
(b) √(mk) t⁻¹/²
(c) √2mk t⁻¹/²
(d) 1/2√(mk) t⁻¹/²
Correct Answer:
√(mk/2) t⁻¹/²
Explanation:
As we know power P = dw / dt
w = Pt = (1/2) mV²
So, v = √(2Pt / m)
Hence, acceleration a = dV / dt = √(2P / m).(1/2√t)
Therefore, force on the particle time ‘t’ = ma
= √(2Km² / m) . (1/2√t) = √(Km / 2t) = √(mK / 2) t⁻¹/₂
Related Questions: - The maximum particle velocity in a wave motion is half the wave velocity.
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- Two particles which are initially at rest, move towards each other
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The maximum particle velocity in a wave motion is half the wave velocity.
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- Two particles which are initially at rest, move towards each other
- The phase difference between two points seperated by 0.8 m in a wave of frequency
- In Young’s double slit experiment, a third slit is made in between the double slits.
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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