A source and an observer approach each other with same velocity 50 m/s. If the frequency

⇦

⇨

A source and an observer approach each other with same velocity 50 m/s. If the frequency is 435 s⁻¹, then the real frequency is (Velocity of sound=332 m/s)

Options

(a) 320 s⁻¹
(b) 360 s⁻¹
(c) 390 s⁻¹
(d) 420 s⁻¹

Correct Answer:

320 s⁻¹

Explanation:

Both the source and the observer are approaching each other with the same velocity. v = 332 m/s v(o) = v(s) = 50 m/s Therefore, n’ = n.[v + v(o)] / [v – v(s)] 435 = n.[(332 + 50) / (332 – 50)] = (n × 382) / 282 n = (435 × 282) / 382 ≈ 321 ≈ 320 s⁻¹

Related Questions:

1. When 4 A current flows for 2 min in an electroplating experiment,
2. A soap bubble oscillates with time period T, which in turn depends on the pressure
3. Which of the following is suitable for the fusion process?
4. The maximum velocity of a particle, executing simple harmonic motion with an amplitude
5. Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless

Topics: Waves (80)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends