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The average power dissipated in a pure inductor is
Options
(a) VI²/4
(b) 1/2 VI
(c) zero
(d) VI²
Correct Answer:
zero
Explanation:
In the inductor circuit, phase difference (ɸ) = 90° or π / 2
we know that, Pₐᵥ = V(rms) I(rms) cos ɸ = V(rms) I(rms) cos(π/2)
Therefore, Pₐᵥ = 0
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Copper and carbon wires are connected in series and the combined resistor is kept
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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