| ⇦ |
| ⇨ |
A proton is moving in a uniform magnetic field B in a circular path of radius a in a direction perpendicular to Z-axis along which field B exists. Calculate the angular momentum. If the radius is a and charge on proton is e.
Options
(a) Be/a²
(b) eB²a
(c) a²eB
(d) aeB
Correct Answer:
a²eB
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
- A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
- Moment of inertia of a uniform circular disc about a diameter is I. Its moment
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
- A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
- Moment of inertia of a uniform circular disc about a diameter is I. Its moment
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply