| ⇦ |
| ⇨ |
Under the action of a force F=cx, the position of a body changes from 0 to x.The work done is
Options
(a) 1/2 Cx ²
(b) Cx ²
(c) Cx
(d) 1/2 Cx
Correct Answer:
1/2 Cx ²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Energy of photon whose frequency is 10¹² MHz will be
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
- In a LCR series circuit, the potential difference between the terminals of the inductor
- The rate of increase of thermo-e.m.f. with temperature at the neutral temperature
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Energy of photon whose frequency is 10¹² MHz will be
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
- In a LCR series circuit, the potential difference between the terminals of the inductor
- The rate of increase of thermo-e.m.f. with temperature at the neutral temperature
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

We know the work done can be 1/2mv^2 therefore it comes as 1/2 cx^2