| ⇦ | 
| ⇨ |
If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Options
(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032
Correct Answer:
0.0164
Explanation:
Here μᵥ=1.5230and μʀ=1.5145
Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187
Now, dispersive power, ω is given by,
ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164
Related Questions: - If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- X-ray beam can be deflected by
- What is the Q-value of the reaction?
¹H+⁷Li→⁴He+⁴He
- A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
- Two cells when connected in series are balanced on 8m on a potentiometer.
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- X-ray beam can be deflected by
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
- A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
- Two cells when connected in series are balanced on 8m on a potentiometer.
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply