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If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Options
(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032
Correct Answer:
0.0164
Explanation:
Here μᵥ=1.5230and μʀ=1.5145
Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187
Now, dispersive power, ω is given by,
ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164
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Topics: Ray Optics
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The relationship between decay constant λ and half-life T of a radioactive substance is
- A parallel beam of light of wavelength λ is incident normally on a narrow slit
- In a n-p-n transistor about 10¹⁰ electrons enter the emitter in 2 μs,
- The radius of curvature of the convex face of a plano-convex lens is 12 cm
- A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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