| ⇦ | 
| ⇨ |
The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T. A proton is shot into the field with velocity v=(2×10⁵i ̂ + 4×10⁵ j ̂ ) m/s. The proton follows a helical path in the field. The distance moved by proton in the x-direction during the period of one revolution in the yz- plane will be (mss of proton=1.67×10⁻²⁷ kg)
Options
(a) 0.053 m
(b) 0.136 m
(c) 0.157 m
(d) 0.236 m
Correct Answer:
0.157 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A liquid boils when its vapour pressure equals
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- A magnifying glass of focal length 5 cm is used to view an object by a person
- If longitudinal strain for a wire is 0.03 and its poisson’s ratio is 0.5
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A liquid boils when its vapour pressure equals
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- A magnifying glass of focal length 5 cm is used to view an object by a person
- If longitudinal strain for a wire is 0.03 and its poisson’s ratio is 0.5
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply