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Three resistances P,Q,R each of 2Ω and an unknown resistances S form the four arms of a Wheatstone bridge circuit. When a resistance of 6Ω is connected in parallel to S the bridge gets balanced. What is the value of S?
Options
(a) 3Ω
(b) 6Ω
(c) 1Ω
(d) 2Ω
Correct Answer:
3Ω
Explanation:
A balanced wheatstone bridge simply requires P/ Q = R / s 2 / 2 = 2 / S
Therefore, S should be 2Ω. A resistance of 6Ω is connected in parallel. In parallel combination,
1/R = 1/R₁ + 1/R₂
1/2 = 1/6 + 1/S
S = 3Ω
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- A magnetic needle suspended parallel to a magnetic field requires √3J of work
- In a LCR series circuit, the potential difference between the terminals of the inductor
- A wire is suspended vertically from one of its ends is stretched by attaching a weight
- A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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