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A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°. The increase in its potential energy is
Options
(a) 2 J
(b) 3 J
(c) 0 J
(d) 1 J
Correct Answer:
1 J
Explanation:
Change in potential energy = mg/(1/2) (1-cosθ)
Given: mass = 400g = 0.4 kg and angle = 60°
Therefore, ∆U = 0.4 × 10 × (1/2) × (1-cos 60°) = 1 J.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The molar specific heat at constant pressure of an ideal gas is (7/2)R. The ratio
- A stone of mass 1kg is tied to a string 4m long and is rotated at constant speed
- The phase difference between the instantaneous velocity and acceleration of a particle
- A body of mass 2 kg travels according to the law x(t)=pt+qt²+rt³
- When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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