| ⇦ | 
| ⇨ |
A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°. The increase in its potential energy is
Options
(a) 2 J
(b) 3 J
(c) 0 J
(d) 1 J
Correct Answer:
1 J
Explanation:
Change in potential energy = mg/(1/2) (1-cosθ)
Given: mass = 400g = 0.4 kg and angle = 60°
Therefore, ∆U = 0.4 × 10 × (1/2) × (1-cos 60°) = 1 J.
Related Questions: - If n₁, n₂ and n₃ are the fundamental frequencies of three segments into which a string
- 180⁰ phase difference is obtained when light ray is reflected from
- Shearing stress causes change in
- The escape velocity of a body on an imaginary planet which is thrice the radius
- Dimensions formula for surface tension is
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If n₁, n₂ and n₃ are the fundamental frequencies of three segments into which a string
- 180⁰ phase difference is obtained when light ray is reflected from
- Shearing stress causes change in
- The escape velocity of a body on an imaginary planet which is thrice the radius
- Dimensions formula for surface tension is
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply