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A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°. The increase in its potential energy is
Options
(a) 2 J
(b) 3 J
(c) 0 J
(d) 1 J
Correct Answer:
1 J
Explanation:
Change in potential energy = mg/(1/2) (1-cosθ)
Given: mass = 400g = 0.4 kg and angle = 60°
Therefore, ∆U = 0.4 × 10 × (1/2) × (1-cos 60°) = 1 J.
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(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For CE transistor amplifier, the audio signal voltage across the collector resistance
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- SI unit of magnetic dipole moment is
- Two stones of masses m and 2m are whirled in horizontal circles, the heavier one
- A student measures the terminal potential difference (V) of a cell
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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